Question

if root 3 sin theta - cos theta = 0,where 0<theta<90 degree ,find the value of theta
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Answer 1

Answer:

$\sqrt{3} \: sin \alpha - cos \alpha = 0 \\ dividing \: both \: side \: by \: 2 \\ \frac{ \sqrt{3} }{2} \: sin \alpha - \frac{1}{2} \: cos \alpha = 0 \\ sin \alpha \: cos30 - cos \alpha \: sin30 = 0 \\ \sin( \alpha - 30) = 0 = sin0 \\ \alpha - 30 = 0 \\ \alpha = 30 \: \: or \: \: \frac{\pi}{6} \: \: ans.$

Answer 2

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