If ( root2-root5/root2+root5=9+b root10, find the value of `a` `b` ?
Answers
Answered by
1
√2-√5/√2+√5=a+b√10
or, a+b√10=(√2-√5)(√2-√5)/(√2+√5)(√2-√5)
or, a+b√10=(√2-√5)²/{(√2)²-(√5)²}
or, a+b√10=(2-2√10+5)/(2-5)
or, a+b√10=(7-2√10)/(-3)
or, a+b√10=(-7/3)+(2/3)√10
Equating both sides,
a=-7/3 and b=2/3
or, a+b√10=(√2-√5)(√2-√5)/(√2+√5)(√2-√5)
or, a+b√10=(√2-√5)²/{(√2)²-(√5)²}
or, a+b√10=(2-2√10+5)/(2-5)
or, a+b√10=(7-2√10)/(-3)
or, a+b√10=(-7/3)+(2/3)√10
Equating both sides,
a=-7/3 and b=2/3
Similar questions