if roots of the equation x2 - 2(1+3m)x-7(3+2m) =0 are equal ,then evaluate m .
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Compare given equation with ax^2+bx+c=0
a=1,
b=-2(1+3m)
c=-7(3+2m)
Roots are equal then
b^2=4ac
[-2(1+3m)]^2=4*1*[-7(3+2m)]
4(1+9m^2+6m)=4*[-21-14m]
Divide with 4 both sides
1+9m^2+6m+21+14m=0
9m^2+20m+22=0
Here we get
m value imaginary number
a=1,
b=-2(1+3m)
c=-7(3+2m)
Roots are equal then
b^2=4ac
[-2(1+3m)]^2=4*1*[-7(3+2m)]
4(1+9m^2+6m)=4*[-21-14m]
Divide with 4 both sides
1+9m^2+6m+21+14m=0
9m^2+20m+22=0
Here we get
m value imaginary number
mysticd:
:)
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