If S and T are two sets such that S has 21 elements, T has 32 elements, and S ∩ T has 11 elements, how many elements does S ∪ T have?
NCERT Solutions for Class 11th Mathematics Chapter 1 Exercise 1.6 4
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Answered by
7
Answer: -
n(S) = 21 n(T) = 32
S ∩ T =11
S ∪ T = ?
we know that ,
S ∪ T = n(S) + n(T) - S ∩ T Substituting the values ,we get
S ∪ T = n(S) + n(T) - S ∩ T =21 + 32 - 11 = 53 - 11 = 42
Hope this helps You!!!
n(S) = 21 n(T) = 32
S ∩ T =11
S ∪ T = ?
we know that ,
S ∪ T = n(S) + n(T) - S ∩ T Substituting the values ,we get
S ∪ T = n(S) + n(T) - S ∩ T =21 + 32 - 11 = 53 - 11 = 42
Hope this helps You!!!
Answered by
2
n(S U T) = 42
Given:
n(S) = 21
n(T) = 32
n(S ⋂ T) = 11
To Find:
n(S U T)
Calculating:
The formula that is used to calculate the union of sets:
n(S U T) = n(S) + n(T) - n(S ⋂ T)
Substituting all the values that are known to us in this formula we get:
n(S U T) = 21 + 32 - 11
n(S U T) = 53 - 11
n(S U T) = 42
Therefore, n(S U T) = 42.
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