If s(x) = 2 – x2 and t(x) = 3x, which value is equivalent to mc023-1.jpg
–439
–141
153
443
Answers
Answered by
37
S(x) = 2 - x^2
t(x) = 3x
(s o t)(x) = s(t(x)) = 2 - (3x)^2 = 2 - 9x^2
(s o t)(-7) = 2 - 9(-7)^2 = 2 - 9(49) = 2 - 441 = -439
Hope it helps
t(x) = 3x
(s o t)(x) = s(t(x)) = 2 - (3x)^2 = 2 - 9x^2
(s o t)(-7) = 2 - 9(-7)^2 = 2 - 9(49) = 2 - 441 = -439
Hope it helps
Answered by
2
Answer:
Since in the question s(x) is given as 2 - x^2 and t(x) is given as 3x then to find the value of s of f we have to place the value of t(x) in the s(x).
Now, (s of t(x))= 2 - (3x)^2.
Then the value of s of t(x) we will get 2 - 9x^2.
So, now putting the value of s of t(x) as (-7) we will get the value as 2-9(-7)^2.
Then, (s*f) = 2 - 441 which will be equal to -439.
Similar questions