Math, asked by martinezd, 1 year ago

If s(x) = 2 – x2 and t(x) = 3x, which value is equivalent to mc023-1.jpg
–439
–141
153
443

Answers

Answered by TheNightHowler
37
S(x) = 2 - x^2
t(x) = 3x
(s o t)(x) = s(t(x)) = 2 - (3x)^2 = 2 - 9x^2
(s o t)(-7) = 2 - 9(-7)^2 = 2 - 9(49) = 2 - 441 = -439
Hope it helps
Answered by AneesKakar
2

Answer:

Since in the question s(x) is given as 2 - x^2 and t(x) is given as 3x then to find the value of s of f we have to place the value of t(x) in the s(x).

Now, (s of t(x))= 2 - (3x)^2.

Then the value of s of t(x) we will get 2 - 9x^2.

So, now putting the value of s of t(x) as (-7) we will get the value as 2-9(-7)^2.

Then, (s*f) = 2 - 441 which will be equal to -439.

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