if sec(7-2x) = cosec (5x-7), then find the valur of x.
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Answered by
1
sec(7-2x) = sec (90-5x-7)
7-2x = 90-5x-7
5x-2x = 90-7-7 = 90-14 = 76
3x = 76
x = 76/3 = 25.3°
The value of x is 25.3°
7-2x = 90-5x-7
5x-2x = 90-7-7 = 90-14 = 76
3x = 76
x = 76/3 = 25.3°
The value of x is 25.3°
ani99ket:
wrong
brackets par dhyan do
thank you for correcting me
edit you answer to correct it
Answered by
3
sec(7-2x)=cosec(5x-7)
cosec[90-(7-2x)]=cosec(5x-7)
90-7+2x=5x-7
83+2x=5x-7
83+7=5x-2x
90=3x
30=x
hence x=30
hope it helps
cosec[90-(7-2x)]=cosec(5x-7)
90-7+2x=5x-7
83+2x=5x-7
83+7=5x-2x
90=3x
30=x
hence x=30
hope it helps
plz do mark my ans as brainliest one
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