Question

If sec A=15/7 and a+b=90 find the value of cosec B

Answer 1

Sec A = 15/7 Cos A = 1/SecA Therefore CosA = 1/ 15/7 = 7/15 

A + B = 90 or A = 90 - B 


CosA = Cos(90-B) 

7/15 = SinB 

CosecB = 1/SinB = 1/ 7/15 = 15/7 

Answer 2

Answer:

secA = cosecB = $\frac{15}{7}$

Explanation:

Given

A+B = 90°

=> A = 90°-B---(1)

and

$secA=\frac{15}{7}$

$\implies sec(90-B)=\frac{15}{7}$

/* From (1) */

$\implies cosecB=\frac{15}{7}$

/* We know that,

sec(90-B) = cosecB */

Therefore,

secA = cosecB = $\frac{15}{7}$

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