Question

If secθ – tanθ = l/3 what is secθ + tanθ?

Answer 1

$3$

it will be 3 very simple as sec^2A-tan^2A=1

which is equal to (secA-tanA)(secA+tanA)

Answer 2

Answer:

sec θ + tan θ = 3.

Step-by-step explanation:

We know that, according to the trigonometric identity,

1  + $tan^{2}$θ = $sec^{2}$θ

$sec^{2}$θ – $tan^{2}$θ = 1

Given expression is sec θ - tan θ = 1/3.

Therefore,

(sec  θ - tan  θ) * (sec θ + tan θ) = 1

==> 1/3 * (sec θ + tan θ) = 1

So,

sec θ + tan θ =  3.

Hope it helps.