If sec+tan=m and sec-tan=n find the value of root mn
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Hey! Here is ur answer...
m = sec x + tan x
n = sec x - tan x
Now, root (mn) = root [(sec x + tan x) (sec x - tan x)]
= root (sec^2 x - tan^2 x)
As we know,
1 + tan^2 x = sec^2 x
=> sec^2 x - tan^2 x = 1
So, root (mn) = root (1) = 1
Hope this helps u...Plz mark it as brainliest... :)
m = sec x + tan x
n = sec x - tan x
Now, root (mn) = root [(sec x + tan x) (sec x - tan x)]
= root (sec^2 x - tan^2 x)
As we know,
1 + tan^2 x = sec^2 x
=> sec^2 x - tan^2 x = 1
So, root (mn) = root (1) = 1
Hope this helps u...Plz mark it as brainliest... :)
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