Question

If secθ + tan θ = p, then what is the value of secθ − tan θ ?

Answer 1

$\textbf{ \underline { Hey there !!}} \:$

Given, secθ + tan θ = p

We know that,
$\mathbf{Since, sec^2 \theta - tan^2 \theta = 1}$
sec²θ - tan²θ = 1

=> secθ + tan θ (secθ − tan θ ) = 1

=> p ( secθ − tan θ ) = 1

=> secθ − tan θ = 1/p

We used the formula : a² - b² = ( a + b) (a - b) and transposed

Final answer :

secθ − tan θ = $\mathbf{ \frac{1}{p}}$

Hope

Answer 2

❤❤Here is your answer ✌ ✌


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