Question

If sec theeta + tan theeta = p, then what is the value of sec theeta - tan theeta​

Answer 1

Answer:

Step-by-step explanation:

Secø + tanø = p —-(1)

We know that,

Sec²ø - tan²ø = 1

(Secø + tan ø)(secø-tanø) = 1

= p(secø -tanø) = 1 ( since secø+tanø=p)

So ,

Secø - tanø = 1/p

Answer 2

Answer:

$\huge \cal \colorbox{gold}{☆Answer☆}$

Secø + tanø = p —-(1)

We know that,

Sec²ø - tan²ø = 1

(Secø + tan ø)(secø-tanø) = 1

= p(secø -tanø) = 1 ( since secø+tanø=p)

So ,

Secø - tanø = 1/p