If sec theta = 2/√3,then find the value of 1-cosec theta/1+cosec theta
Answers
Answered by
23
Sec A = 2/√3
sec A= Sec 30
A = 30
so
1-cosecA/1+cosecA
1-cosec30/1+cosecA
1-2/1+2 -1/3
answer -1/3
sec A= Sec 30
A = 30
so
1-cosecA/1+cosecA
1-cosec30/1+cosecA
1-2/1+2 -1/3
answer -1/3
aniketkabaddi01:
is it right???
Answered by
17
Answer:
1 - cosec θ/1 + cosec θ = -1/3
Step-by-step explanation:
Solution :
Sec θ = 2/√3
We know that, sec 30º = 2/√3
∴ θ = 30⁰
Cosec θ = Cosec 30° = 2
1 - cosec θ/1 + cosec θ
= 1 - cosec 30⁰/1 + cosec 30⁰
= 1-2/1+ 2
= -1/3
∴ The value of 1 - cosec θ/1 + cosec θ = -1/3.
Similar questions