Math, asked by Mahinyoosaf3067, 1 year ago

If sec theta = 2/√3,then find the value of 1-cosec theta/1+cosec theta

Answers

Answered by aniketkabaddi01
23
Sec A = 2/√3
sec A= Sec 30
A = 30

so
1-cosecA/1+cosecA
1-cosec30/1+cosecA
1-2/1+2 -1/3

answer -1/3

aniketkabaddi01: is it right???
Answered by adityadolas2605
17

Answer:

1 - cosec θ/1 + cosec θ = -1/3

Step-by-step explanation:

Solution :

Sec θ = 2/√3

We know that, sec 30º = 2/√3

∴ θ = 30⁰

Cosec θ = Cosec 30° = 2

1 - cosec θ/1 + cosec θ

= 1 - cosec 30⁰/1 + cosec 30⁰

= 1-2/1+ 2

= -1/3

∴ The value of 1 - cosec θ/1 + cosec θ = -1/3.

Similar questions