if sec theta -tan theta =x, show that sec theta + tan theta =1/x and hence find the value of cos theta and sin theta
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Answered by
137
The answer is given below :
Given that,
secθ - tanθ = x .....(i)
We know that,
sec²θ - tan²θ = 1
=> (secθ + tanθ)(secθ - tanθ) = 1
=> (secθ + tanθ) × x = 1
=> secθ + tanθ = 1/x
So, secθ + tanθ = 1/x [Proved]
secθ + tanθ = 1/x .....(ii)
Now, adding (i) and (ii), we get
2 secθ = x + 1/x
=> secθ = 1/2 (x² + 1)/x
=> cosθ = 2x/(x² + 1)
So, cosθ = 2x/(x² + 1)
Now,
sinθ = [√{(x² + 1)² - (2x)²}]/(x² + 1)
= (x² - 1)/(x² + 1)
Thank you for your question.
Given that,
secθ - tanθ = x .....(i)
We know that,
sec²θ - tan²θ = 1
=> (secθ + tanθ)(secθ - tanθ) = 1
=> (secθ + tanθ) × x = 1
=> secθ + tanθ = 1/x
So, secθ + tanθ = 1/x [Proved]
secθ + tanθ = 1/x .....(ii)
Now, adding (i) and (ii), we get
2 secθ = x + 1/x
=> secθ = 1/2 (x² + 1)/x
=> cosθ = 2x/(x² + 1)
So, cosθ = 2x/(x² + 1)
Now,
sinθ = [√{(x² + 1)² - (2x)²}]/(x² + 1)
= (x² - 1)/(x² + 1)
Thank you for your question.
Answered by
57
first rationalise sec theta - tan theta
then add equation 1 & 2 u will get the value of cos theta
subtract 1 & 2 for sin theta
then add equation 1 & 2 u will get the value of cos theta
subtract 1 & 2 for sin theta
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