Question

If secA=m and tanA=n, then 1/m[(m+n)+(1/m+n)]=

Answer 1

hope this helps you.. :)

Answer 2

Hello!

Here is your answer

Sec a, = m

Tan a, = n

$\frac{1}{m}( (m + n) + \frac{1}{m} + n)$

Cos a ( sec a + tan a) + (cos a + tan a)

Cos a Tan a ( sec a + cos a)

Tan a ( 1 + Cos^2 a)