if secA-tanA = a,
then the value of sinA =
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we know that sec^2 A - tan^2 A =1 and it is given that
sec A -tan A =a
dividing equation 1 with 2, we get
sec A + tan A = 1/a
also sec A - tan A = a
adding and subtracting these equations, we get
sec A = (a + 1/a )/2
& tan A = (1/a -a)/2
thus, sin A = (sin A/ cos A) / (1/cos A) = tan A / sec A =( 1-a^2) / (1+ a^2)
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