If seco + tano = p, then find the value of coseco ( here o represents theta)
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Answered by
0
Answer:
h+o /a
Step-by-step explanation:
this is the answer
Answered by
3
Answer:
sec0+tan0=p. then seco-tan0=1/p
as sec2o -tan2o=1
add 1 and 2
2seco=p+1/p
seco=p2+1/2p
as p2+1= hypoteneuse
2p=base
perpendicular= p2-1
coseco= p2+1/p2-1
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