Question

if sin 0 + cosec 0 = 2, then sin 6 0 + cosec 6 0 is equal to​

Answer 1

$\huge \mathbb\red{answer}$

$sin0 + cosec0 = 2 \\ \\ then \: as \: we \: know \: 1 + 1 = 2 \: so \: sin0 = 1 \: then \: \sin(90) \\ \\ similarly \: cosec(0) = 1 \: ie \: cosec(90) \\ \\ so \: value \: of \: 0 = 90$

$now \: sin60 = \frac{ \sqrt{3} }{2} \: and \: cosec60 \frac{2}{ \sqrt{3} } \\ \\ so \: \frac{ \sqrt{3} }{2} + \frac{2}{ \sqrt{3} } \\ \frac{3 + 4}{2 \sqrt{3} } \\ \\ \frac{7}{2 \sqrt{3} }$

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