Question

If sin = 1/3, then find the value of 2cot^2 + 2.​

Answer 1

Answer:

sin=1/3=P/H

p^2+ b^2= h^2

1+ b^2= 9

b^2= 8

b=√8

cot=b/p

cot= √8/1

2×(√8)^2+2

2×8+2

=16+2

=18

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