Question

If sin (36 + θ)^o = cos (16 + θ)^o, then find θ, where (36 + θ)^o and (16 + θ)^o are both acute angles.

Answer 1

sin (36+Q) =cos (90-(36+Q))

then our equation become

cos(90 - (36+Q)) = cos(16+Q)


90-36-Q=16+Q

54-16=Q+Q
38=2Q
Q=19
Q is an acute angle《19》