Question

if sin 3A =cos(A-26),where 3A is an acute angle ,find the value of A.​

Answer 1

Answer:sin 3A = cos (A-26°)or, sin 3A = sin {90° - (A-26°)}or, 3A = 90° - A + 26°or, 4A = 116°or, A = 116°/4or, A = 29°Hope it will help you.........please mark me as Brainliest..

Answer 2

Answer:

• 29°

Step-by-step explanation:

Given

• sin 3A = cos(A - 26)
• Where 3A is an acute angle

To find

• A

Solution

↪ sin 3A = cos(90° - 3A)

→ cos(90° - 3A) = cos(A - 26°)

→ 90° - 3A and A - 26° are acute angles, so:

• 90° - 3A = A - 26°
• A = 29°

(An acute angle is an angle that measures less than 90 degrees)

Must know

⟶ sin(90° - A) = cos A

⟶ tan(90° - A) = cot A

⟶ sec(90° - A) = cosec A

⟶ cos(90° - A) = sin A

⟶ cot(90° - A) = tan A  

⟶ cosec(90° - A) = sec A