If sin (50degree - 3/2alpha ) = cos (3alpha - 50degree), then find value of alpha
Answers
Answered by
1
sin(50°-3/2α)=cos(3α-50°)
or, sin(50°-3/2α)=sin{90°-(3α-50°)} [∵, sin(90°-α)=cosα]
or, 50°-3/2α=90°-3α+50°
or, -3/2α=90°-3α
or, 3α-3/2α=90°
or, (6α-3α)/2=90°
or, 3α=90°×2
or, α=180°/3
or, α=60° Ans.
or, sin(50°-3/2α)=sin{90°-(3α-50°)} [∵, sin(90°-α)=cosα]
or, 50°-3/2α=90°-3α+50°
or, -3/2α=90°-3α
or, 3α-3/2α=90°
or, (6α-3α)/2=90°
or, 3α=90°×2
or, α=180°/3
or, α=60° Ans.
Similar questions