If sin (A + 2B ) =√3 /2 and cos (A + 4B ) =0. Find A and B.
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Answered by
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sin(A+2B)=√3/2
sin(A+2B)=sin60 {sin60=√3/2}
on comparing---
A+2B=60---eq.1
cos(A+4B)=0
cos(A+4B)=cos90 {cos90=0}
on comparing ---
A+4B=90----eq. 2
on subtracting eq.1 by eq.2
A+4B-A-2B=90-60
2B=30
B=15°
put in eq.1
A=30°
sin(A+2B)=sin60 {sin60=√3/2}
on comparing---
A+2B=60---eq.1
cos(A+4B)=0
cos(A+4B)=cos90 {cos90=0}
on comparing ---
A+4B=90----eq. 2
on subtracting eq.1 by eq.2
A+4B-A-2B=90-60
2B=30
B=15°
put in eq.1
A=30°
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