Question

If sin A=3/5, prove that tan A+(1/cos A)=2 or -2

Answer 1

sinA=3/5 perpendicular /base
so calculating cos A by pythogoras we get cos A=4/5.......(25=+9)...x=4 or x=-4
tanA =sinA/cosA
3/5 upon 4/5= 3/4  or 3/5 upon -4/5
substituting the value in the given equation
3/4+5/4  or -3/4 -5/4............(1/cos A =sec A=5/4 or sec A=-5/4)
which is equal to 2 or -2

Answer 2

Answer:

Proved

Step-by-step explanation:

sin A = 3/5   {sin A = P/H}

B^2 = H^2 - P^2 ⇒ 25-9=16

B= 4

tan A = P/B ⇒ 3/4

1/cos A= sec A⇒ H/B = 5/4

substituting value in given equation

3/4+5/4 = 8/4 = 2

Hence proved