Question

If sin (a+b)=1 and cos (a-b)=root3/2,0 lees than a+b less than 90 and a less than b then a and b are

Answer 1

I hope it helps your

Answer 2

sin(a+b)=1
we know , [sin 90 = 1]
hence, a+b = 90 ------------- (1)
 ...........................
cos (a-b) = root3/2
we know , cos  30 = root3/2 -------------------(2)
hence , a-b= 30
 FROM 1 AND 2 
a+b =90 and a-b= 30
adding (1) and (2) 
2a= 120
a=60
since , a+b = 90
b=90-60=30
hence,
a=60
b=30......but since it is specified a<b and since cos(-[a-b])= cos(a-b)
a=30 degree and b= 60 degree