if sin(theta)=√3/2, find the value of all T-ratios of theta.
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Thank you for asking this question:
sin θ = -√3/2 = - sin π/3 = sin 4πr/3
sinθ = sin 4πr/3
θ = nπ + (-1)^n (4π/3)
Now we will put the value of n here
n = 1,2,3,4,5,6
means we can get the 6 different values when trying to find n.
If there is any confusion please leave a comment below.
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