Question

if sin theta is equal to 3 by 5 then find the value of cos theta minus 1 by 10 theta by 2 cos theta​

Answer 1

$\sin( \alpha) = \frac{3}{5} \\ \\ \\ \frac{ \cos( \alpha ) - 1 }{ \frac{ \tan( \alpha ) }{2 \cos( \alpha ) } } \\ \frac{ \frac{4}{5} - 1 }{ \frac{ \frac{3}{4} }{2 \times \frac{4}{5} } }$

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