If sin(thita) =1/5 then calculate value of cos(thita)
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sin thita= 1/5 = p/h
and cos thita = b/h
so p= 1, h= 5 by pythagorus theorum.
hsqu..= psqu..+ bsqu..
so b= 25-1 =24 which is your b squ..
so, cos thita = b/h = root 24/25
and cos thita = b/h
so p= 1, h= 5 by pythagorus theorum.
hsqu..= psqu..+ bsqu..
so b= 25-1 =24 which is your b squ..
so, cos thita = b/h = root 24/25
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