Question

if sin3A=cos(A-26°) where 3A is an acute angle . find the value of A .​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given :

Sin 3A = Cos(A - 26°)

Formula used :

$sin \: \theta = cos(90 - \theta)$

Solution :

Sin 3A = Cos(A - 26°)

cos(90° - 3A) = cos(A - 26°)

Comparing angles

90 - 3A = A - 26

90 + 26 = A + 3A

116 = 4A

A = 116/4

A= 29°

So, the value of A is 29°