If sin5theta=cos4theta where 5theta and 4theta are acute angles .Find the value of theta
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Answer :
Now, sin5θ = cos4θ
⇒ cos (90 - 5θ) = cos4θ,
since sinθ = cos (90 - θ)
⇒ 90 - 5θ = 4θ
⇒ 4θ + 5θ = 90
⇒ 9θ = 90
⇒ θ = 90/9
⇒ θ = 10
We see that, 5θ = 50° and 4θ = 40°; both are acute angles.
Therefore, the value of θ is 10°
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Now, sin5θ = cos4θ
⇒ cos (90 - 5θ) = cos4θ,
since sinθ = cos (90 - θ)
⇒ 90 - 5θ = 4θ
⇒ 4θ + 5θ = 90
⇒ 9θ = 90
⇒ θ = 90/9
⇒ θ = 10
We see that, 5θ = 50° and 4θ = 40°; both are acute angles.
Therefore, the value of θ is 10°
#MarkAsBrainliest
Answered by
4
Sin5Ф = Cos4Ф
⇒ Cos(90 - 5Ф) = Cos4Ф [cos(90-Ф)= sinФ]
⇒ 90 - 5Ф = 4Ф
⇒ 90 = 4Ф + 5Ф
⇒ 90 = 9Ф
⇒ 90/9 = Ф
⇒ 10 = Ф
Value of theta is 10°
i hope this will help you
(-:
⇒ Cos(90 - 5Ф) = Cos4Ф [cos(90-Ф)= sinФ]
⇒ 90 - 5Ф = 4Ф
⇒ 90 = 4Ф + 5Ф
⇒ 90 = 9Ф
⇒ 90/9 = Ф
⇒ 10 = Ф
Value of theta is 10°
i hope this will help you
(-:
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