The perimeter of a rhombus is 52 cm and one diagonal is 24 cm . what is the length of the other diagonal
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Answered by
0
The perimeter of rhombus is 52 cm
Measure of one side = 52/4
= 13 cm
Half of d1 = 12 cm
Half of d2² = 13²-12²
=√(169-144)
= √25
= 5 cm
d2 = 2*5 = 10 cm
Therefore, the measurement of other diagonal is 10 cm.
Hope this helpz :)
Measure of one side = 52/4
= 13 cm
Half of d1 = 12 cm
Half of d2² = 13²-12²
=√(169-144)
= √25
= 5 cm
d2 = 2*5 = 10 cm
Therefore, the measurement of other diagonal is 10 cm.
Hope this helpz :)
Answered by
7
Heya !!!
Let ABCD is a rhombus.
In which,
AC and BD are it's diagonals.
Let AC = 24 cm
Perimeter of rhombus = 52 cm
4 × Side = 52 cm
Side (AB) = 52/4 = 13 cm
We know that,
The diagonals of a rhombus bisect each other at right Angles.
Therefore,
OA = OC = 1/2 × AC = 1/2 × 24 = 12 cm
By pythagoras theroem,
AB = (OA)² + (OB)²
13² = (12)² + (OB)²
169 = 144 + OB²
OB² = 169-144
OB² = 25
OB = ✓25 = 5 cm
Therefore,
Diagonal BD = 2 × OB = 2 × 5= 10 cm
HOPE IT WILL HELP YOU.... :-)
Let ABCD is a rhombus.
In which,
AC and BD are it's diagonals.
Let AC = 24 cm
Perimeter of rhombus = 52 cm
4 × Side = 52 cm
Side (AB) = 52/4 = 13 cm
We know that,
The diagonals of a rhombus bisect each other at right Angles.
Therefore,
OA = OC = 1/2 × AC = 1/2 × 24 = 12 cm
By pythagoras theroem,
AB = (OA)² + (OB)²
13² = (12)² + (OB)²
169 = 144 + OB²
OB² = 169-144
OB² = 25
OB = ✓25 = 5 cm
Therefore,
Diagonal BD = 2 × OB = 2 × 5= 10 cm
HOPE IT WILL HELP YOU.... :-)
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