Question

If SINA=4/5 And COSB=5/13 find COS(A-B/2)
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Answer 1

SinA=12/15
cosB=4/5=sinB=5/4=
sin(A+B)=12/13×5/4
=12×5/13×4=15/13
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Answer 2

Answer:

IN triangle AHG

SIN=OPP/HYP

SO HYP=5

OPP=4

BY PYTHAGORAS THEOREM

HYP^2=OPP^2+ADJ^2

5^2=4^2+ADJ^2

ADJ^2=5^2-4^2

ADJ^2=25-16

ADJ^2=9

ADJ=3

COS A=3/5

COS A-B/2=3/5-5/13/2

=39/63-25/63/2

=14/63/2/1

=7/63

=1/9=0.11

IN THIS /2 IS DENOMINATOR

SO 14/63/2

=14/63*1/2

=7/63=>1/9

I HOPE THIS HELPS U

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Step-by-step explanation: