find the largest no. of four digits which is exactly divisible by 12,15,18,27
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Solution:
The Largest number of four digits is 9999.
Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.
On dividing 9999 by 540,we get 279 as remainder .
\Required number = (9999-279) = 9720.
The Largest number of four digits is 9999.
Required number must be divisible by L.C.M. of 12,15,18,27 i.e. 540.
On dividing 9999 by 540,we get 279 as remainder .
\Required number = (9999-279) = 9720.
ramakantasahoo:
5x+6y-xy=30 find the value of x and y?
sorry can't find the answers
ok
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0
Answer:9720 would be the answer
Step-by-step explanation:
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