Question

PQ is a tangent at a point R of the circle with centre O. If angle TRQ=30°,find angle PRS.​

Answer 1

Answer:

«❤ANSWER ❤»

Given ∠TRQ = 30°.

At point R, OR ⊥ RQ.

∠ORQ = 90°

⇒ ∠TRQ + ∠ORT = 90°

⇒ ∠ORT = 90° − 30° = 60°

ST is diameter, ∠SRT = 90° [∵ Angle in semicircle = 90°]

∠ORT + ∠ SRO = 90°

∠SRO + ∠PRS = 90°

∠PRS = 90° − 30° = 60°

Answer 2

Answer:

here is ur answer

=60°

Step-by-step explanation:

plz look at above pic.

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