Math, asked by meghakatiyar1, 1 year ago

If sinA + cos2A = 1/2 and cosA+sin2A = 1/3, then find the value of sin3A.

Answers

Answered by naavyya

3

Answer:

-59/72

Step-by-step explanation:

Attachments:

Answered by komaljangrajangra

0

Answer:

Step-by-step explanation:

SinA+cos2A=1/2 - 1

CosA+sin2A=1/3 - 2

Then,

Adding 1 and 2 equation

SinA+cos2A+cosA+sin2A=1/2+1/3

Sin3A+cos3A=5/6

Sin3A=5/6-Cos3A

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