Question

if sinA =cosA , 0<90°, then the angel A is egual to​

Answer 1

Answer:

A is equal to 45°

Step-by-step explanation:

We know that sinA = cosA at ∅ = 45°.  [0 < 90°]

At ∅ = 45°, sin45° = cos45° = $\frac{1}{\sqrt{2} }$