Question

if sina +cosa =1,then find the value of sinacosa​

Answer 1

Answer:

$\sin( \alpha ) + \cos( \alpha ) = 1 \\ { (\sin( \alpha ) + \cos( \alpha ) ) }^{2} = {1}^{2}=1 \\ { \sin}^{2} ( \alpha ) + {\cos}^{2} ( \alpha ) + 2 \sin( \alpha) \cos( \alpha ) = 1 \\ 1 + 2 \sin( \alpha ) \cos( \alpha) = 1 \\2\sin( \alpha ) \cos( \alpha ) = 0 \\ \sin( \alpha ) \cos( \alpha ) = 0$

0 is the right answer.

Answer 2

Answer is zero, hope it helped