Question

if sinø=√3/2, find the value of (cosecø +cotø)​

Answer 1

$\huge{\underline{\underline{\red{\mathfrak{Answer :}}}}}$

Note : Here I am using α instead of theta.

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As we are given,

Sinα = √3/2

⇒Sinα = Sin60°

⇒α = 60°

We get value of α or say we get angle.

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Now,

A.T.Q,

We have to find value of

(Cosecα + Cotα)

Put Value of α

⇒(Cosec60° + Cot60°)

Put these Values

⇒(2/√3 + 1/√3)

⇒3/√3

So,

Value of Cosecα + Cotα is 3/√3

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#answerwithquality

#BAL

Answer 2

Answer:

Sin= P/H

P= root 3, H= 2

So by pythagoras theorem

B= 1

Cosec + cot

H/P + B/P

2/root 3 + 1/root 3

= 3/ root3

= then we write 3 to root 3 into root 3

So root3 into root3 / root3

= root3

May be it helps you