Question

If sinx=6/10, then find the value of cosx +tanx

Answer 1

Answer:

31/20

Step-by-step explanation:

refer the image to get the answer

Answer 2

Answer:

31/20

Step-by-step explanation:

sinx=6/10=P/H

So, P=6a ; H=10a                [:P=perpendicular,B=base,H=hypotenuse]

then, B=$\sqrt{(H^{2} -P^{2})}$

     B=$\sqrt{(10a)^{2}-(6a)^{2}}$

    B=$\sqrt{100a^{2}-36a^{2}}$

   B=√64a²

  B=8a

So,tanx=P/B=6a/8a=6/8=3/4

   cosx=B/H=8a/10a=8/10=4/5

cosx+tanx=4/5 +3/4= (16+15)/20

                     = 31/20