Question

If sinx* is equal to sin alpha the find the value of alpha​

Answer 1

Answer:

We have,

sinθ=sin∝⇒sinθ−sin∝=0⇒2cos

2

θ+α

sin

2

θ−α

∴Either, cos

2

θ+α

=0 or sin

2

θ−α

=0

for cos

2

θ+α

=0⇒

2

θ+α

=

2

(2n+1)π

Similarly,

sin

2

θ−α

=0⇒

2

θ−α

=nπ

Step-by-step explanation:

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