If speed of train is increased by 5kmph from the normal speed
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The question is incomplete, here is the complete question:
A train travels at a speed of 200 km/h with an increase of 5 km/h every 5 seconds. How much distance will the train cover in 45 minutes?
Answer:
Travelling at 200km/hr it travels 200*5/3600 = 0.2777777777 km in 5 secs.
45 minutes = 45*60 = 2700 secs and these 2700/5 = 540 increments of 5 sec each.
The distance covered in 45 mins (or 2700 secs) is a summation of an AP whose first term is 0.2777777777, number of terms is 540 and the common difference is 0.2777777777.
S540 = (540/2)[2*0.2777777777 + (540–1)*0.2777777777]
= 270[ (2+539)*0.2777777777]
= 270*541*0.2777777777
= 40575 km.
Answer = 40575 km.
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