Question

If sum of a zeroes of a polynomialp(x)=x^3-3kx^2-x+30 is 6 find k?

Answer 1

Given => x³ - 3kx² - x + 30

Here,

a = 1
b = -3k
c = -1
d = 30

Sum of zeroes of polynomial = 6

So,

α + β + γ = 6

= -b/a

Therefore,

3k/1 = 6

k = 6/3

k = 2

Answer 2

Heya !!!


P(X) = X³-3KX²-X+30


Here,


A = 1 , B = -3K , C = -1 and D = 30


Sum of zeroes = -B/A


6 = -(-3K)/1



3K = 6

K = 6/3 = 2




HOPE IT WILL HELP YOU....... :-)