if sum of n terms of an AP is 2n²+5 then prove that an=4n+3
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a1=2 (1)^2+5(1)=7
s2=2 (2)^2+5(2)=18
a2=s2-a1=18-7=11
an= (7)+(n-1)4=4n+3
your question is wrong
Sum of n terms=2n^2+5n
s2=2 (2)^2+5(2)=18
a2=s2-a1=18-7=11
an= (7)+(n-1)4=4n+3
your question is wrong
Sum of n terms=2n^2+5n
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