Question

if sum of three terms in AP is 33 and sum of their squares is 365 find the ap​

Answer 1

Answer:

the ap is 10, 11 , 12

Step-by-step explanation:

let the three numbers be a-d, a, a+d

sum = a+ a-d +a+d = 3a

but sum is given as 33

which implies 3a = 33

hence, a = 11 --------------(i)

also the sum of their squares is given as 365

so, a² + a²+d² +2ad + a² + d² -2ad = 365

3a² + 2d² = 365

putting a = 11

3x121 +2d² = 365

2d²= 365 -363

d= 1

hence the ap is 10,11,12

Answer 2

Answer:

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