If sum of two numbers is 820 and difference is 80 then find the numbers
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Here's ur answer dear :)
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Let the numbers be x and y.
Then,
x + y = 820 -------------(1)
x - y = 80 -------------(2)
On Adding both the equations (1) and (2).
We get;
x + y + x - y = 820 + 80
=> 2x = 900 [ y - y cancelled ]
=> x = 900/2
=> x = 450
And,
x + y = 820
=> 450 + y = 820
=> y = 820 - 450
=> y = 370.
Hence the required numbers are
Thanks for the question!
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