Question

if t11=16, t21=29, find 41 th term​

Answer 1

Answer:

t11 = 16

a +10d = 16 — 1

t21 = 29

a + 20d = 29 — 2

using 1,2 in elimination method

a +10d = 16

a + 20d = 29

- - -

———————–

- 10d = -13

d = 13/10

put value of d in 1

a + 10×13/10 = 16

a + 13 = 16

a = 16-13

a = 3

t41 = a + 40d

= 3 + 40×13/10

= 3 + 52

= 55

follow me on brainly

Answer 2

Step-by-step explanation:

Given that:

T11= 16

that is 16 =t+15d

and

T21 = 29

that is 29=t+20d

for further calculation take a look at the attachment.

thnx mark me as brainliest,rate, thank