If t2-1 is a factor of at3+t2-2t+b find a and b
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Let p(t) = at3 + t2- 2t + b
Factorize t2- 1 as t2- 12 = (t-1)(t+1)
As t2- 1 is a factor of p(t)
Therefore, (t-1)(t+1) are also the factors of p(t)
p(1) = a(1)3+(1)2- 2(1)+ b
0 = a+ 1- 2+ b
0 = a- 1+ b
1 = a+ b
OR
a + b = 1 (1)
Also, p(-1) = a(-1)3+(-1)2- 2(-1)+ b
0 = -a+ 1+ 2+ b
3 = b - a
OR
b - a = 3 (2)
ADDING (1) and (2) -
a + b = 1
-a + b = 3
--------------
0 + 2b = 4
b = 4/2
b = 2
Substituting value of ' b ' in (1)
a + b = 1
a + 2 = 1
a = 1 - 2 = -1
Therefore , a = (-1)
b = 2
Factorize t2- 1 as t2- 12 = (t-1)(t+1)
As t2- 1 is a factor of p(t)
Therefore, (t-1)(t+1) are also the factors of p(t)
p(1) = a(1)3+(1)2- 2(1)+ b
0 = a+ 1- 2+ b
0 = a- 1+ b
1 = a+ b
OR
a + b = 1 (1)
Also, p(-1) = a(-1)3+(-1)2- 2(-1)+ b
0 = -a+ 1+ 2+ b
3 = b - a
OR
b - a = 3 (2)
ADDING (1) and (2) -
a + b = 1
-a + b = 3
--------------
0 + 2b = 4
b = 4/2
b = 2
Substituting value of ' b ' in (1)
a + b = 1
a + 2 = 1
a = 1 - 2 = -1
Therefore , a = (-1)
b = 2
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