If tan^2 θ−3sec θ+3=0 , where 0∘<θ<90∘, then the value of sinθ+cotθ
Answers
Answered by
0
Answer:
surname chicken biscuit
Answered by
0
Answer:
Step-by-step explanation:
tan^2x-3(1+tan^2x)+3=0
tan^2x-3-3tan^2x+3=0
-2tan^2 x=0
tanx=0
x=90o
then ,
sin x+cotx=sin 90o+cot90o=1
Similar questions