Question

If tan^2 θ−3sec θ+3=0 , where 0∘<θ<90∘, then the value of sinθ+cotθ

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

tan^2x-3(1+tan^2x)+3=0

tan^2x-3-3tan^2x+3=0

-2tan^2 x=0

tanx=0

x=90o

then ,

sin x+cotx=sin 90o+cot90o=1