Question

if tan^2 45°- cos^2 60° = x×sin^2 45°×tan60°

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Answer 1

Answer:

tan^2 45 - cos^2 60 = x × sin^45 ×tan 60

1 - 1/4 = x × 1/4 ×root 3

3/4 = x× 3^1/2/4

3= x× 3^1/2

x= root 3

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Answer 2

HEY MATE YOUR ANSWER IS....

${ \tan }^{2} 45 - { \cos}^{2}60 = x { \sin}^{2} 45 \times { \tan }^{2}61$

★ NOW BY TRIGNOMATERIC VALUES ★

$\tan45 = 1 \\ \\ \cos60 = \frac{1}{2} \\ \\ \sin45 = \frac{1}{ \sqrt{2} } \\ \\ \tan60 = \sqrt{3}$

★ SOLUTION ★

${(1)}^{2} - {( \frac{1}{2}) }^{2} = x { (\frac{1}{ \sqrt{2} } )}^{2} \times { (\sqrt{3}) }^{2}$

$1 - \frac{1}{4} = x \times \frac{1}{2} \times 3$

$\frac{4 - 1}{4} = x \times \frac{3}{2}$

$\frac{3}{4} = x \times \frac{3}{2}$

$x = \frac{3}{4} \times \frac{2}{3}$

$x = \frac{1}{2}$

THANKS FOR YOUR QUESTION HOPE THIS HELPS....

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