If tan 2A =cot (A-18°), where 2A and A - 18° are acute angles, find the value of A
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Answered by
38
tan2A= cotA (A-18 )
cot (90-2A)=cotA(A-18)
90-2A=A-18
90+18= 3A
108=3A
A= 36
cot (90-2A)=cotA(A-18)
90-2A=A-18
90+18= 3A
108=3A
A= 36
Answered by
5
Answer:Tan2a=cot A(A-18) sol=cot (90-2a)=cota(A-18)
90-2a=a-18
90+18=3a
108=3a
A=36
Step-by-step explanation:
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