Question

If tan =

9

40

, find sin , cos.​

Answer 1

Answer:

Sin Values

sin 0° = √(0/4) = 0

sin 30° = √(1/4) = ½

sin 45° = √(2/4) = 1/√2

sin 60° = √3/4 = √3/2

sin 90° = √(4/4) = 1

Cos Values

cos 0° = √(4/4) = 1

cos 30° = √(3/4) = √3/2

cos 45° = √(2/4) = 1/√2

cos 60° = √(1/4) = 1/2

cos 90° = √(0/4) = 0

Tan Values

tan 0° = 0/1 = 0

tan 30° = [(√1/4)/√(3/4)] = 1/√3

tan 45° = √(2/4) = 1/√2

tan 60° = [(√3/2)/(½)] = √3

tan 90° = 1/0 = ∞

Hence, the sin cos tan values are found.